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Q49

NAT2 marks

Consider a 100  Mbps100 \; \text{Mbps} link between an earth station (sender) and a satellite (receiver) at an altitude of 2100  km.2100 \; \text{km}. The signal propagates at a speed of 3×108  m/s.3 \times 10^{8} \; \text{m/s.} The time taken (in milliseconds,  rounded off to two decimal places)\text{(in milliseconds,} \; \textit{rounded off to two decimal places}) for the receiver to completely receive a packet of 1000  bytes1000 \; \text{bytes} transmitted by the sender is _______________.

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