GA Q3MCQ1 mark, −0.33Let rrr be a root of the equation x2+2x+6=0.x^{2} + 2x + 6 = 0.x2+2x+6=0. Then the value of the expression (r+2)(r+3)(r+4)(r+5)(r+2) (r+3) (r+4) (r+5)(r+2)(r+3)(r+4)(r+5) is(A)515151(B)−51-51−51(C)126126126(D)−126-126−126Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google