Q66MCQ2 marks, −0.5Let A=11111010A = 1111 1010A=11111010 and B=00001010B = 0000 1010B=00001010 be two 8−bit8-bit8−bit 2’s2’s2’s complement numbers. Their product in 2’s2’s2’s complement is(A)110001001100 010011000100(B)100111001001 110010011100(C)101001011010 010110100101(D)110101011101 010111010101Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google