Q24MCQ1 mark, −0.25Consider the binary relation: S={(x,y)∣y=x+1 and x,y∈{0,1,2}}S= \left\{\left(x, y\right) \mid y=x+1 \text{ and } x, y \in \left\{0, 1, 2\right\} \right\}S={(x,y)∣y=x+1 and x,y∈{0,1,2}} The reflexive transitive closure is SSS is(A){(x,y)∣y>x and x,y∈{0,1,2}}\left\{\left(x, y\right) \mid y >x \text{ and } x, y \in \left\{0, 1, 2\right\} \right\}{(x,y)∣y>x and x,y∈{0,1,2}}(B){(x,y)∣y≥x and x,y∈{0,1,2}}\left\{\left(x, y\right) \mid y \geq x \text{ and } x, y \in \left\{0, 1, 2\right\} \right\}{(x,y)∣y≥x and x,y∈{0,1,2}}(C){(x,y)∣y<x and x,y∈{0,1,2}}\left\{\left(x, y\right) \mid y < x \text{ and } x, y \in \left\{0, 1, 2\right\} \right\}{(x,y)∣y<x and x,y∈{0,1,2}}(D){(x,y)∣y≤x and x,y∈{0,1,2}}\left\{\left(x, y\right) \mid y \leq x \text{ and } x, y \in \left\{0, 1, 2\right\} \right\}{(x,y)∣y≤x and x,y∈{0,1,2}}Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google