GA Q8MCQ2 marks, −0.67Which one of the following options is correct for the given data in the table? Iteration (i)0123Input (I)20-41015Output (X)20162641Output (Y)20-80-800-12000\begin{array}{|c|c|c|c|c|} \hline \text{Iteration (i)} & \text{0} & \text{1} & \text{2} & \text{3} \\ \hline \text{Input (I)} & \text{20} & \text{-4} & \text{10} & \text{15} \\ \hline \text{Output (X)} & \text{20} & \text{16} & \text{26} & \text{41} \\ \hline \text{Output (Y)} & \text{20} & \text{-80} & \text{-800} & \text{-12000} \\ \hline \end{array}Iteration (i)Input (I)Output (X)Output (Y)02020201-416-8021026-80031541-12000(A)X(i)=X(i−1)+I(i); Y(i)=Y(i−1)I(i); i>0X(i) = X(i-1)+I(i); \: \: Y(i) = Y(i-1)I(i); \: \: i>0X(i)=X(i−1)+I(i);Y(i)=Y(i−1)I(i);i>0(B)X(i)=X(i−1)I(i); Y(i)=Y(i−1)+I(i); i>0X(i) = X(i-1)I(i); \: \: Y(i) = Y(i-1)+I(i); \: \: i>0X(i)=X(i−1)I(i);Y(i)=Y(i−1)+I(i);i>0(C)X(i)=X(i−1)I(i); Y(i)=Y(i−1)I(i); i>0X(i) = X(i-1)I(i); \: \: Y(i) = Y(i-1)I(i); \: \: i>0X(i)=X(i−1)I(i);Y(i)=Y(i−1)I(i);i>0(D)X(i)=X(i−1)+I(i); Y(i)=Y(i−1)I(i−1); i>0X(i) = X(i-1)+I(i); \: \: Y(i) = Y(i-1)I(i-1); \: \: i>0X(i)=X(i−1)+I(i);Y(i)=Y(i−1)I(i−1);i>0Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google