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Q45

NAT2 marks

Given a computing system with two levels of cache (L1 and L2) and a main memory. The first level (L1) cache access time is 11 nanosecond (ns) and the "hit rate" for L1 cache is 90%90 \% while the processor is accessing the data from L1 cache. Whereas, for the second level (L2) cache, the "hit rate" is 80%80 \% and the "miss penalty" for transferring data from L2 cache to L1 cache is 1010 ns . The "miss penalty" for the data to be transferred from main memory to L2 cache is 100100 ns . Then the average memory access time in this system in nanoseconds is __________ . (rounded off to one decimal place)

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