Q1.2MCQ1 mark, −0.25An n×nn \times nn×n array vvv is defined as follows: v[i,j]=i−jv\left[i,j\right] = i - jv[i,j]=i−j for all i,j,i≤n,1≤j≤ni, j, i \leq n, 1 \leq j \leq ni,j,i≤n,1≤j≤n The sum of the elements of the array vvv is(A)000(B)n−1n-1n−1(C)n2−3n+2n^2 - 3n +2n2−3n+2(D)n2(n+1)2n^2 \frac{\left(n+1\right)}{2}n22(n+1)Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google