Q4MCQMarks unknownLet GGG be a finite group and HHH be a subgroup of GGG. For a∈Ga \in Ga∈G, define aH={ah∣h∈H}aH=\left\{ah \mid h \in H\right\}aH={ah∣h∈H}.(A)Show that ∣aH∣=∣bH∣.|aH| = |bH|.∣aH∣=∣bH∣.(B)Show that for every pair of elements a,b∈Ga, b \in Ga,b∈G, either aH=bHaH = bHaH=bH or aHaHaH and bHbHbH are disjoint.(C)Use the above to argue that the order of HHH must divide the order of G.G.G.Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google