Q3-iiiMSQMarks unknownThe number of rooted binary trees with nnn nodes is,(A)Equal to the number of ways of multiplying (n+1)(n+1)(n+1) matrices.(B)Equal to the number of ways of arranging nnn out of 2n2 n2n distinct elements.(C)Equal to 1(n+1)(2nn)\frac{1}{(n+1)}\binom{2n}{n}(n+1)1(n2n).(D)Equal to n!n!n!.Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google