Q29MCQ2 marks, −0.67Let ppp, qqq and rrr be propositions and the expression (p→q)→r\left ( p\rightarrow q \right )\rightarrow r(p→q)→r be a contradiction. Then, the expression (r→p)→q\left ( r\rightarrow p \right )\rightarrow q(r→p)→q is(A)a tautology(B)a contradiction(C)always TRUE when ppp is FALSE(D)always TRUE when qqq is TRUESign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google