Q38MCQ2 marks, −0.67The grammar S→aSa∣bS∣c S \to aSa \mid bS \mid cS→aSa∣bS∣c is(A)LL(1) but not LR(1)(B)LR(1) but not LL(1)(C)Both LL(1) and LR(1)(D)Neither LL(1) nor LR(1)Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google