Q3MCQ1 mark, −0.25Let P(E)P(E)P(E) denote the probability of the event EEE. Given P(A)=1P(A) = 1P(A)=1, P(B)=12P(B) =\dfrac{1}{2}P(B)=21, the values of P(A∣B)P(A\mid B)P(A∣B) and P(B∣A)P(B\mid A)P(B∣A) respectively are(A)(14),(12)\left(\dfrac{1}{4}\right),\left(\dfrac{1}{2}\right)(41),(21)(B)(12),(14)\left(\dfrac{1}{2}\right),\left(\dfrac{1}{4}\right)(21),(41)(C)(12),1\left(\dfrac{1}{2}\right),{1}(21),1(D)1,(12){1},\left(\dfrac{1}{2}\right)1,(21)Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google