Q2.7MCQMarks unknownThe probability that top and bottom cards of a randomly shuffled deck are both aces is(A)452×452\frac{4}{52} \times \frac{4}{52}524×524(B)452×352\frac{4}{52} \times \frac{3}{52}524×523(C)452×351\frac{4}{52} \times \frac{3}{51}524×513(D)452×451\frac{4}{52} \times \frac{4}{51}524×514Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google