Q92,xvMCQMarks unknownWhich of the following predicate calculus statements is/are valid?(A)(∀(x))P(x)∨(∀(x))Q(x) ⟹ (∀(x))(P(x)∨Q(x))(\forall (x)) P(x) \vee (\forall(x))Q(x) \implies (\forall (x)) (P(x) \vee Q(x))(∀(x))P(x)∨(∀(x))Q(x)⟹(∀(x))(P(x)∨Q(x))(B)(∃(x))P(x)∧(∃(x))Q(x) ⟹ (∃(x))(P(x)∧Q(x))(\exists (x)) P(x) \wedge (\exists (x))Q(x) \implies (\exists (x)) (P(x) \wedge Q(x))(∃(x))P(x)∧(∃(x))Q(x)⟹(∃(x))(P(x)∧Q(x))(C)(∀(x))(P(x)∨Q(x)) ⟹ (∀(x))P(x)∨(∀(x))Q(x)(\forall (x)) (P(x) \vee Q(x)) \implies (\forall (x)) P(x) \vee (\forall (x)) Q(x)(∀(x))(P(x)∨Q(x))⟹(∀(x))P(x)∨(∀(x))Q(x)(D)(∃(x))(P(x)∨Q(x)) ⟹ ∼(∀(x))P(x)∨(∃(x))Q(x)(\exists (x)) (P(x) \vee Q(x)) \implies \sim (\forall (x)) P(x) \vee (\exists (x)) Q(x)(∃(x))(P(x)∨Q(x))⟹∼(∀(x))P(x)∨(∃(x))Q(x)Sign in to save attempts.Show answer← PreviousSolutionsDiscussionLoading…Sign in with Google