GA Q3

MCQ1 mark, −0.33

If $\theta$ is the angle, in degrees, between the longest diagonal of the cube and any one of the edges of the cube, then, $\cos \theta =$

(A)

$\frac{1}{2}$

(B)

$\frac{1}{\sqrt{3}}$

(C)

$\frac{1}{\sqrt{2}}$

(D)

$\frac{\sqrt{3}}{2}$

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