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Q44

NAT2 marks

Consider Guwahati, (G)(G) and Delhi (D)(D) whose temperatures can be classified as high (H)(H), medium (M)(M) and low (L)(L). Let P(HG)P(H_G) denote the probability that Guwahati has high temperature. Similarly, P(MG)P(M_G) and P(LG)P(L_G) denotes the probability of Guwahati having medium and low temperatures respectively. Similarly, we use P(HD), P(MD)P(H_D),\: P(M_D) and P(LD)P(L_D) for Delhi. The following table gives the conditional probabilities for Delhi’s temperature given Guwahati’s temperature.

HDMDLDHG0.400.480.12MG0.100.650.25LG0.010.500.49\begin{array}{|c|c|c|c|} \hline & H_D & M_D & L_D \\ \hline H_G & 0.40 & 0.48 & 0.12 \\ \hline M_G & 0.10 & 0.65 & 0.25 \\ \hline L_G & 0.01 & 0.50 & 0.49 \\ \hline \end{array}

Consider the first row in the table above. The first entry denotes that if Guwahati has high temperature (HG)(H_G) then the probability of Delhi also having a high temperature (HD)(H_D) is 0.40;0.40; i.e., P(HD∣HG)=0.40P(H_D \mid H_G) = 0.40. Similarly, the next two entries are P(MD∣HG)=0.48 and P(LD∣HG)=0.12P(M_D \mid H_G) = 0.48 \text{ and } P(L_D \mid H_G) = 0.12. Similarly for the other rows. If it is known that P(HG)=0.2, P(MG)=0.5P(H_G) = 0.2, \: P(M_G) = 0.5, and P(LG)=0.3P(L_G)=0.3, then the probability (correct to two decimal places) that Guwahati has high temperature given that Delhi has high temperature is ________.

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