Q40MCQ2 marks, −0.5Consider numbers represented in 4-bit Gray code. Let h3h2h1h0 h_{3}h_{2}h_{1}h_{0}h3h2h1h0 be the Gray code representation of a number nnn and let g3g2g1g0 g_{3}g_{2}g_{1}g_{0}g3g2g1g0 be the Gray code of (n+1)(modulo16) (n+1)(modulo 16)(n+1)(modulo16) value of the number. Which one of the following functions is correct?(A)g0(h3h2h1h0)=∑(1,2,3,6,10,13,14,15)g_{0}(h_{3}h_{2}h_{1}h_{0})=\sum (1,2,3,6,10,13,14,15)g0(h3h2h1h0)=∑(1,2,3,6,10,13,14,15)(B)g1(h3h2h1h0)=∑(4,9,10,11,12,13,14,15)g_{1}(h_{3}h_{2}h_{1}h_{0})=\sum (4, 9,10,11,12,13,14,15)g1(h3h2h1h0)=∑(4,9,10,11,12,13,14,15)(C)g2(h3h2h1h0)=∑(2,4,5,6,7,12,13,15)g_{2}(h_{3}h_{2}h_{1}h_{0})=\sum (2, 4,5,6,7,12,13,15)g2(h3h2h1h0)=∑(2,4,5,6,7,12,13,15)(D)g3(h3h2h1h0)=∑(0,1,6,7,10,11,12,13)g_{3}(h_{3}h_{2}h_{1}h_{0})=\sum (0,1,6,7,10,11,12,13)g3(h3h2h1h0)=∑(0,1,6,7,10,11,12,13)Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google