Q30MCQ2 marks, −0.67Consider the recurrence function T(n)={2T(n)+1,n>22,0<n≤2T(n) = \begin{cases} 2T(\sqrt{n})+1, & n>2 \\ 2, & 0 < n \leq 2 \end{cases}T(n)={2T(n)+1,2,n>20<n≤2 Then T(n)T(n)T(n) in terms of Θ\ThetaΘ notation is(A)Θ(loglogn)\Theta(\log \log n)Θ(loglogn)(B)Θ(logn)\Theta( \log n)Θ(logn)(C)Θ(n)\Theta (\sqrt{n})Θ(n)(D)Θ(n)\Theta(n)Θ(n)Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google