Q27NAT2 marksConsider the recurrence relation a1=8,an=6n2+2n+an−1a_1 =8 , a_n =6n^2 +2n+a_{n-1}a1=8,an=6n2+2n+an−1. Let a99=K×104a_{99}=K\times 10^4a99=K×104. The value of KKK is __________.Sign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google