Q5MCQ1 mark, −0.33In the following truth table, V=1V = 1V=1 if and only if the input is valid. InputsOutputsD0D1D2D300001000x100xx10xxx1X0X1Vxx0001011101111\begin{array}{cc} \textbf{Inputs}&\textbf{Outputs}\\ \begin{array}{|c|c|c|c|} \hline {D_0}&D_1&D_2&D_3 \\ \hline 0&0&0&0 \\ \hline 1&0&0&0 \\ \hline \text{x}&1&0&0 \\ \hline \text{x}&\text{x}&1&0 \\ \hline \text{x}&\text{x}&\text{x}&1 \\ \hline \end{array}& \begin{array}{|c|c|c|} \hline X_0&X_1&V \\ \hline \text{x}&\text{x}&0\\ \hline 0&0&1\\ \hline 0&1&1\\ \hline 1&0&1\\ \hline 1&1&1\\ \hline \end{array} \\ \end{array}InputsD001xxxD1001xxD20001xD300001OutputsX0x0011X1x0101V01111 What function does the truth table represent?(A)Priority encoder(B)Decoder(C)Multiplexer(D)DemultiplexerSign in to save attempts.Show answer← PreviousNext →SolutionsDiscussionLoading…Sign in with Google