GATEverse
← GATE CSE 2009

Q36

MCQ2 marks, −0.67

The keys 12,18,13,2,3,23,512, 18, 13, 2, 3, 23, 5 and 1515 are inserted into an initially empty hash table of length 1010 using open addressing with hash function h(k)=kmod  10h(k) = k \mod 10 and linear probing. What is the resultant hash table?

Sign in to save attempts.

Loading…