Q2.8

MCQMarks unknown

If the cube roots of unity are $1, \omega$ and $\omega^2$ , then the roots of the following equation are

(x-1)^3 +8 =0

(A)

$-1, 1 + 2\omega, 1 + 2\omega^2$

(B)

$1, 1 - 2\omega, 1 - 2\omega^2$

(C)

$-1, 1 - 2\omega, 1 - 2\omega^2$

(D)

$-1, 1 + 2\omega, -1 + 2\omega^2$

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